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Appendix 2

In this note we prove that a covariance matrix is non-negative definite.

Consider the product, H, that is the product of an arbitrary vector, a, and the covariance vector, x:


\begin{displaymath}H = a^T E[ (x - \mu) (x - \mu)^T ] a
\end{displaymath} (1)

We can re-arrange the above by moving the constant vector a inside expectation operator so that we have,


\begin{displaymath}H = E[ a^T(x - \mu) (x - \mu)^T a]
\end{displaymath} (2)

If we define

\begin{displaymath}Y \equiv (x - \mu)^T a
\end{displaymath} (3)

(which is a random variable because x is), then (2) is

H = E[ YT Y] (4)

This ``squared'' quantity is clearly never negative, so that we can conclude that the covariance matrix $E[ (x - \mu) (x - \mu)^T ]$ is non-negative definite.








Q.E.D



Skip Carter
1999-12-09